Question

A space probe is to be put into a circular orbit of radius 42.00 km about an asteroid. At this radius the magnitude of the gravitational acceleration, normally referred to as the "gravitational field", is 1.00×10-3 meters per second squared. What speed, in meters per second, must the probe be given relative to the asteroid for this orbit to be achieved?

my first idea is to solve this problem by f=ma but then i cant do it

Answer 1

v^2=rg v=sqrt(42000*1*10^-3)=6.5m/s