Asked by Anon
A 300mL solution was made by dissolving 5.0g of MgCl2 in water. What is its molarity?
Answers
Answered by
DrBob222
mols MgCl2 = grams/molar mass
Then M = mols/L solution
Then M = mols/L solution
Answered by
Twaha
300ml solution equals to 0.5 g mgcl2
1ml " " "0.5/300 "
1000ml " " " (0.5*1000)/300g "
1.667M (ans.)
1ml " " "0.5/300 "
1000ml " " " (0.5*1000)/300g "
1.667M (ans.)
Answered by
DrBob222
What you have posted is pure blarney.
First error: 300 mL solution equals 5 g MgCl2 and not 0.5. The problem says 300 mL solution and 5.0 g MgCl2.
Second error: you are trying to base molarity on solution/grams and it should be mols/L solution.
The correct solution is as follows:
300 mL contains 5.0 MgCl2 (molar mass 95.2).
mols MgCl2 = 5.0/95.2 = approx 0.0525
M = mols/L = 0.0525/0.300 = 0.175M
First error: 300 mL solution equals 5 g MgCl2 and not 0.5. The problem says 300 mL solution and 5.0 g MgCl2.
Second error: you are trying to base molarity on solution/grams and it should be mols/L solution.
The correct solution is as follows:
300 mL contains 5.0 MgCl2 (molar mass 95.2).
mols MgCl2 = 5.0/95.2 = approx 0.0525
M = mols/L = 0.0525/0.300 = 0.175M
Answered by
Twaha
i'm sorry. I didn't understand the question properly. Thank u for showing my mistakes.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.