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A puck of mass 0.165 kg, initially resting on ice, is hit by a stick to gain a speed of 32.0 m/s and then slides 25.0 m to lose 5.00% of its kinetic energy. (a) What is the work done on the puck by the stick? (b) What is the kinetic friction coefficient between the ice and puck?
10 years ago

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bobpursley
work done on puck=1/2 masspuck*v^2

initiial KE-finalKE=mg*mu

1/2 m vi^2-1/2 (.95vi)^2=mg*mu

solve for mu.
10 years ago

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