Asked by julius
f(x,y)=2xe^y-3ye^-x derive second order
Answers
Answered by
Steve
I think you mean find the second derivative. Do you mean partial derivatives? There are three.
Fx = 2e^y + 3ye^-x
Fy = 2xe^y - 3e^-x
Fxx = -3ye^-x
Fyy = 2xe^y
Fxy = Fyx = 2e^y + 3e^-x
Fx = 2e^y + 3ye^-x
Fy = 2xe^y - 3e^-x
Fxx = -3ye^-x
Fyy = 2xe^y
Fxy = Fyx = 2e^y + 3e^-x
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