A 1300kg car going 20m/s has to stop suddenly. The driver locks the brakes, and the car skids to a halt in a distance of 64m .

What was the car's acceleration while stopping?
How much work was done by friction to stop the car?
What is the coefficient of kinetic friction between tires and road?

User Icon for bobpursley bobpursley answered
10 years ago

vf^2=vi^2+2ad solve for a

work=KE of car initially
or work=force*distance=ma*distance
force=mu(mg)=ma
mu=a/g

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the car's acceleration while stopping, you can use the kinematic equation:

v^2 = u^2 + 2as

Where:
v = final velocity = 0 m/s (since the car comes to a halt)
u = initial velocity = 20 m/s (given)
a = acceleration (to be determined)
s = displacement = 64 m (given)

Rearranging the equation, we have:

a = (v^2 - u^2) / (2s)

Substituting the given values, we get:

a = (0^2 - 20^2) / (2 * 64)
a = (-400) / 128
a = -3.125 m/s^2

Therefore, the car's acceleration while stopping is -3.125 m/s^2 (negative sign indicates deceleration).

To calculate the work done by friction to stop the car, we can use the work-energy principle. The work done is equal to the change in kinetic energy of the car:

Work = ΔKE
Work = 1/2 * m * (v^2 - u^2)

Substituting the given values, we have:

Work = 1/2 * 1300 kg * (0^2 - 20^2)
Work = 1/2 * 1300 kg * (-400)
Work = -1/2 * 1300 kg * 400
Work = -260,000 joules

Therefore, the work done by friction to stop the car is -260,000 joules (negative sign indicates work against the direction of motion).

To find the coefficient of kinetic friction between the tires and the road, we can use the equation:

Force of friction = coefficient of friction * normal force

Since the car is skidding, the frictional force opposes the motion. It can be calculated using the equation:

Force of friction = mass * acceleration

Substituting the given values, we have:

mass * acceleration = coefficient of friction * normal force

Since the car is stopping, the acceleration is the deceleration we previously calculated: -3.125 m/s^2.

Therefore:

1300 kg * (-3.125 m/s^2) = coefficient of friction * normal force

Simplifying, we have:

coefficient of friction = (1300 kg * -3.125 m/s^2) / normal force

Unfortunately, we don't have the normal force information, so we cannot determine the coefficient of kinetic friction between the tires and the road without additional data.