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A 1340 kg car going 21 m/s has to stop suddenly. The driver locks the brakes, and the car skids to a halt in a distance of 67 m...Asked by Anonymous
A 1300kg car going 20m/s has to stop suddenly. The driver locks the brakes, and the car skids to a halt in a distance of 64m .
What was the car's acceleration while stopping?
How much work was done by friction to stop the car?
What is the coefficient of kinetic friction between tires and road?
What was the car's acceleration while stopping?
How much work was done by friction to stop the car?
What is the coefficient of kinetic friction between tires and road?
Answers
Answered by
bobpursley
vf^2=vi^2+2ad solve for a
work=KE of car initially
or work=force*distance=ma*distance
force=mu(mg)=ma
mu=a/g
work=KE of car initially
or work=force*distance=ma*distance
force=mu(mg)=ma
mu=a/g
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