Question
How much work is done lifting a wrecking ball 6.50 m above the ground?
So the formula for this problem would be:
W=fs F=200kg S=6.50m
(200)(6.50)=1300
So the formula for this problem would be:
W=fs F=200kg S=6.50m
(200)(6.50)=1300
Answers
ben green
I forgot to add the wrecking ball weighs 200kg
Steve
the problem is, 200kg is the mass, not the weight. You forgot to multiply by g=9.81
You did W = ms, not W=fs
If you had kept track of the units, you'd have spotted your error.
kg * m ≠ work
You did W = ms, not W=fs
If you had kept track of the units, you'd have spotted your error.
kg * m ≠ work