y = (4x-8)/(x+1)
y' = 12/(x+1)^2
So,
y(0) = -8
y'(0) = 12
Now you have a point (0,-8) and a slope (12), so the tangent line is
y = 12x-8
See
http://www.wolframalpha.com/input/?i=plot+y%3D%284x-8%29%2F%28x%2B1%29%2Cy%3D12x-8+for+x+%3D+-1+to+3
Find the equation of the tangent line to the graph of
f(x) = (4x − 8)/(x + 1)
at
x = 0.
(Use y for your dependent variable.)
1 answer