Asked by morgan

(-9x^3-6x^2-x+3)/(2x^2+5x+2)

I have figured out the equation for the slant asymptote = (33/4)-(9x/2) but this next ? is throwing me off. I have tried graphing and everything and it doesnt seem to work.

What is the smallest value of x at which f(x) intersects its non-vertical asymptote? (Leave this question blank if you answered no above.)
Answered by Steve
well, just plug it in:

33/4 - 9x/2 = (-9x^3-6x^2-x+3)/(2x^2+5x+2)

http://www.wolframalpha.com/input/?i=solve+33%2F4+-+9x%2F2+%3D+%28-9x^3-6x^2-x%2B3%29%2F%282x^2%2B5x%2B2%29

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