Asked by Maria
The electron in a hydrogen atom in level n= 8 undergoes a transition to a lower leve by emitting a photon of wavelength 956 mom. What is the final level of the electron?
A) 4
B) 8
C) 9
D) 1
E) 3
A) 4
B) 8
C) 9
D) 1
E) 3
Answers
Answered by
bobpursley
1/lambda=R*Z^2 (1/n1^2-1/n2^2)
or (1/n1^2-1/n2^2)=1/lambda*R
Lambda*R=956nm*1.097E7=10.48
and the reciprocal of that is .0954
1/n1^2-1/64=.0954
1/n1^2=.111
n1= sqrt (9)=3
or (1/n1^2-1/n2^2)=1/lambda*R
Lambda*R=956nm*1.097E7=10.48
and the reciprocal of that is .0954
1/n1^2-1/64=.0954
1/n1^2=.111
n1= sqrt (9)=3
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