Did I do #2 right?

Question

2.) (1-2i)/2i

(1-2i)/2i
= (1-2)/i x i/i
= (1i-2i)/i^2
= (1i+2)
=2+1i

Answer 1

Recall that since i^2 = -1, 1/i = -i

(1-2i)/(2i) = 1/(2i) - (2i)/(2i)
= 1/2 (-i) - 1
= -1 - 1/2 i