Asked by Anna
what heading must a pilot fly to compensate for a 125km/h west wind to have a ground track that is due south? The airecraft cruise speed is 600 km/h. What is the actual ground speed?
Answers
Answered by
Henry
a. Vpg + Vw = 600km/h[-90o] = -600i
Vpg + 125 = -600i
Vpg = -125 - 600i
Tan Ar = Y/X = -600/-125 = 4.80
Ar = 78.23o = Reference angle.
A = 78.23 + 180 = 258.23o CCW = 11.8o W.
of S. = Heading.
b. Vpg = Y/sin A = -600/sin258.23 = 613
613 km/h. = Velocity of plane relative to gnd.
Vpg + 125 = -600i
Vpg = -125 - 600i
Tan Ar = Y/X = -600/-125 = 4.80
Ar = 78.23o = Reference angle.
A = 78.23 + 180 = 258.23o CCW = 11.8o W.
of S. = Heading.
b. Vpg = Y/sin A = -600/sin258.23 = 613
613 km/h. = Velocity of plane relative to gnd.
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