Question

1.) If a = 2 and the vertex of a parabola is (3, -4), will there be a minimum or maximum value for the parabola? What is the value?


2.) If a = 2 and the vertex of a parabola is (3, -4), what is its axis of symmetry?

Answer 1

1.
equation will be y = 2(x-3)^2 - 4
since the parabola opens upwards, there will be a minimum
That minimum is -4 and it occurs when x = 3

2. same equation
if your equation is y = a(x-p)^2 + q
the vertex is (p,q)
it will open up if a>0
it will open down if a< 0
the axis of symmetry will be x-p=0 or x = p
the max/min will be q , when x = p