Asked by Desirai
A given solution contained potassium chloride, KCl, and hydrochloric acid. 25 cm3 of it needed 24.80 cm3 of 0.0986 M sodium hydroxide solution to neutralize the acid, and the neutral solution then required 23.55 cm3 of 0.2 M silver nitrate, AgNO3, solution to precipitate all of the chloride as silver chloride, AgCl. Calculate the concentration in g dm-3 of potassium chloride and hydrochloric acid in the solution.
Answers
Answered by
DrBob222
mols HCl = M NaOH x L NaOH - ?
mols KCl+HCl = M AgNO3 x L AgNO3 = ?
mols KCl = (mols KCl+HCl)-mols HCl(from NaOH data)
g HCl = mols HCl x molar mass HCl = ?g HCl in the 25 cc.
g KCl = mols KCl x molar mass KCl = ?g KCl in th 25 cc.
Convert g in 25 cc to g/dm^3
mols KCl+HCl = M AgNO3 x L AgNO3 = ?
mols KCl = (mols KCl+HCl)-mols HCl(from NaOH data)
g HCl = mols HCl x molar mass HCl = ?g HCl in the 25 cc.
g KCl = mols KCl x molar mass KCl = ?g KCl in th 25 cc.
Convert g in 25 cc to g/dm^3
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