Asked by Sam
the points (1,4), (3,8) and (8,3) lie on the graph whose equation is of the form: y=a|x-b|+c where a,b and c are real numbers. find a,b and c.
Answers
Answered by
Steve
well, just plug in the points:
a|1-b|+c = 4
a|3-b|+c = 8
a|8-b|+c = 3
a = -2, b = 17/4, c = 21/2
a|1-b|+c = 4
a|3-b|+c = 8
a|8-b|+c = 3
a = -2, b = 17/4, c = 21/2
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