Question

During baseball practice, you go up into the bleachers to retrieve a ball. You throw the ball back into the playing field at an angle of 42° above the horizontal, giving it an initial velocity of 15 m/s. If the ball is 5.3 m above the level of the playing field when you throw it, what will be the velocity of the ball when it hits the ground of the playing field?

Answer 1

I assume you want final speed, not velocity.

final KE=Initial KE+initial PE
1/2 m vf^2=1/2 m(15)^2 +mg(5.3)
solve for Vf