Asked by mathew
Following oxidation-reduction reaction by using the oxidation state method
a) O2+H2O+Pb=Pb(OH)2
a) O2+H2O+Pb=Pb(OH)2
Answers
Answered by
DrBob222
basic solution.
Pb + 2OH^- ==> Pb(OH)2 + 2e
O2 + 4e + 2H2O ==> 2OH^- + 2OH^-
Multiply equation 1 by 2 and equation 2 by 1 and add. Cancel any ions/molecules common to both sides.
Pb + 2OH^- ==> Pb(OH)2 + 2e
O2 + 4e + 2H2O ==> 2OH^- + 2OH^-
Multiply equation 1 by 2 and equation 2 by 1 and add. Cancel any ions/molecules common to both sides.
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