Asked by Issac

A stunt car driver drives off an
h = 6.7 m-high cliff into a lake with a horizontal speed of 14 m/s. The car needs to clear an 8.0 m-long ledge that is 5.0 m below the edge of the cliff. The car successfully misses the ledge on the way down. With what speed does the car hit the water?

Answers

Answered by bobpursley
initial KE+initial PE=final KE
1/2 m 14^2 + mg*6.7=1/2 m vf^2

vf^2=1/2 * 228+9.8*6.7
solve vf
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