Asked by Cherie
Rectangle ABCD has been subdivided into 4 regions. The areas of two of these regions are a^2 and 144. The combined area of the other two regions is 25a. What is the perimeter of the rectangle ABCD?
Please help and show steps! I don't have a clue how to do this. Thank you for your time and help.
Please help and show steps! I don't have a clue how to do this. Thank you for your time and help.
Answers
Answered by
Reiny
Are you sure the sum of the other two regions is 25a and not 24a ?
then the sum of the area would be
a^2 + 144 + 24a
= (a+12)^2
which would make it a square of sides a+12
for a perimeter of 4a + 48
then the sum of the area would be
a^2 + 144 + 24a
= (a+12)^2
which would make it a square of sides a+12
for a perimeter of 4a + 48
Answered by
Steve
True, but we also have
(a+9)(a+16) = a^2 + 25a + 144
(a+9)(a+16) = a^2 + 25a + 144
Answered by
Annie
4a+50
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