Asked by Shahab Mirza

Equal weights of methane and hydrogen are mixed in an empty container at 25 C. the fraction of total pressure exerted by the hydrogen is?
answer is 1/9

i want to know that how to find out this answer thanks?
Answered by bobpursley
you have to compare mole relations...

assume 100 grams of each
moles of H2=50
mole methane=100/16)=about6.25
total moles=56.25

ratio of H2 to total moles: 6.25/56.25=1/9
Answered by Shahab Mirza
@bobpursley , thanks , but what if we solve it like this bro.
= ch4 has 16 molar mass, h2 has 2 molar mass, 1 mol ch4 contains 8 mol H2 .

= moles of ch4 / moles of h2 + moles of ch4

= 1 / 8 + 1
= 1/9

answer in theoretical form.

is it okay?
Answered by DrBob222
1/8 + 1 = 1/9? I don't think so.
1/8 + 1 = 1/8 + 8/8 = 9/8 :-0
Answered by Shahab Mirza
@DrBob222 , someone solved it like this way but i was also wondering that how he got 1/9 :/ , these questions come in our MCAT , and have weird testing pattern, even many of students fail to answer such deep questions , we are given only 1 min to solve such questions .
Answered by DrBob222
You are right. 1/8 + 1 is not 1/9.
Answered by Anonymous
@DrBob222 , exactly Sir, i don't know why they are designing such way to meaningless questions
Answered by abi
it might be 1/(8+1) and he/she must be missing () brackets
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