Question

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car A traveled 22 mph faster than Car B.

How fast did Car A travel?


_______MPH

Answer 1

distancea=timea*speeda
distanceb=timeb*speedb

setting them equal
timea*speeda=timeb*speedb
you are given the two times, and speeda=speedb+22

so

2.4*(speedb+22)=4*speedb
with a little manipulation
speedb(2.4-4)=-2.4*22
speedb=you can do it.

Answer 2

I hav ccbfv