No it isn't. Go back and look at that work I did for you last night. You have smatterings right but you've incorrectly interpreted what I wrote in several places.
mols HCl = 53/36.5 = ?
mols NaOH = same as mols HCl because of the 1:1 ratio.
g NaOH = mols NaOH x molar mass NaOH.
The 1.325 is not right either. You have 53 g HCl and not 53 g/mol.
530 mL solution 10% HCl has been spilt onto the bench. It cannot be diluted or washed away. How much of the granular NaOH from the container seen in a must be used to neutralise the acid? [Using NaOH: MM = 40 g/mol]
1. I have NaOH + HCl --> NaCl + H2O.
10% HCI in a 530ml solution equals to 53grams/molar mass. Therefore 53 g/mol divided by 40g/mol Naoh = 1.325g/mol of NaOH to neutralise the HCL as 1.325g/mol x 40mm of NaOH equals 53g and therefore will neutralise the HCL (53g/mm) as HCI and NaOH have a 1.1 mole ratio.
Is this correct if not how do I convert it to grams?
thankyou guys.
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1 answer