Asked by Ade
Complete the following reactions by moving only one proton at a time. Identify the acid
(A) and the base (B) on the left-hand side of the equation, and the conjugate acid (CA)
and the conjugate base (CB) on the right-hand side of the equation, according to
Bronsted-Lowry theory. The first one has been done for you as an example.
Example: HCO3
- (aq) + H2S (aq) ↔ H2CO3 (aq) + HS- (aq)
B A CA CB
a.) HNO2 (aq) + H2O (l) ↔
b.) CO3
2- (aq) + HBr (aq) ↔
c.) H2C6H5O7
- (aq) + H2SO4 (aq) ↔
(A) and the base (B) on the left-hand side of the equation, and the conjugate acid (CA)
and the conjugate base (CB) on the right-hand side of the equation, according to
Bronsted-Lowry theory. The first one has been done for you as an example.
Example: HCO3
- (aq) + H2S (aq) ↔ H2CO3 (aq) + HS- (aq)
B A CA CB
a.) HNO2 (aq) + H2O (l) ↔
b.) CO3
2- (aq) + HBr (aq) ↔
c.) H2C6H5O7
- (aq) + H2SO4 (aq) ↔
Answers
Answered by
DrBob222
And your problem is??
For a).
HNO2(aq) + H2O(l) ↔ H3O^+(aq) + NO2^-(aq)
Now you look at thwich has more H and which has fewer.
HNO2 is the acid
NO2^- on the right is the conjugate base.
H2O on the left is the base.
H3O^+ on the right is the conjugate acid.
For a).
HNO2(aq) + H2O(l) ↔ H3O^+(aq) + NO2^-(aq)
Now you look at thwich has more H and which has fewer.
HNO2 is the acid
NO2^- on the right is the conjugate base.
H2O on the left is the base.
H3O^+ on the right is the conjugate acid.
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