Asked by kayla

an arresting device on a carrier deck stops an airplane in 1.5s. the avg. acceleration was 49 m/s2. what was the stopping distance? what was the initial speed? so i think v2=0, t=1.5, a= 49, so i need d and v1. i got v1=73.5 m/sec and d= 55 m. i took 0=v1-49(1.5) to get that v1. and also 73.5(1.5)-1/2 (49) (1.5)^2 to get d=55.12 m. Is this correct?

Answers

Answered by bobpursley
d=1/2 a t^2=1/2*49*1.5^2

correct.
Answered by Han
i am not sure
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