Asked by Victoria
A model rocket is shot straight into the air. Its height in meters a "t" seconds is given by h=-4.9^2+29.4t.
a) What is the rocket's initial height?
c)When does the rocket reach the ground?
a) What is the rocket's initial height?
c)When does the rocket reach the ground?
Answers
Answered by
Reiny
h = -4.9t^2 + 29.4t
for the initial height, t = 0 , so h = 0
"reach the ground" implies h = 0
-4.9t^2 + 29.4t = 0
t(-4.9t + 29.4) = 0
so t = 0 ----> the initial time and height
or
t = 29.4/4.9 = 6
so it will return to the ground after 6 seconds
for the initial height, t = 0 , so h = 0
"reach the ground" implies h = 0
-4.9t^2 + 29.4t = 0
t(-4.9t + 29.4) = 0
so t = 0 ----> the initial time and height
or
t = 29.4/4.9 = 6
so it will return to the ground after 6 seconds
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