Asked by aithusa20
A 42 kg girl is bouncing on a trampoline. During a certain interval after she leaves the
surface of the trampoline, her kinetic energy decreases to 250 J from 520 J. How high
does she rise during this interval?
surface of the trampoline, her kinetic energy decreases to 250 J from 520 J. How high
does she rise during this interval?
Answers
Answered by
Henry
KE+PE = 520 J.
250 + PE = 520
PE = 520-250 = 270 J.
mg*h = 270
h = 270/m*g = 270/(42*9.8) = 0.656 m.
250 + PE = 520
PE = 520-250 = 270 J.
mg*h = 270
h = 270/m*g = 270/(42*9.8) = 0.656 m.
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