F(x)=2sin(3x/2-3pi/4)+2

cos^4 x - sin^4 x = 1 - 2sin^2 x Prove

2sin(x)cos(x)+cos(x)=0 I'm looking for exact value solutions in [0, 3π] So I need to find gene...

2Sin(Θ+47°)=1 ΘЄ[0°, 360°) What I did: Sin(Θ+47°)=1/2 Sin 1/2 = Θ+47° 30°+360 = Θ+47° 343...

how does 2sin(a/2)cos(((m+1)/2)a) = sin(((m+2)/2)a) - sin ((ma)/2)?

2sin^2x-1=0[0,2pi)

cos^2(x/2)-sin^2(x/2) 2sin(x/2)cos(x/2)

1-2sin^2(2x)

2sin(4t)[(cos(3/2)x)(cos(5x/2)-sin((15/4)x)]+x

2sin(4x)[(cos(3/2)x)(cos(5x/2)-sin((15/4)x)]+x can someone simplify this using trig identities?

Y=-2sin pi/4(x+1/2)+3

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