Asked by Feather
Use half-cells to balance the following redox reaction, and label the oxidation and reduction half-reactions.
Also, note that bromide is a spectator ion and can be eliminated.
FeBr(aq) +Mg(s) = Fe(s) + MgBr2(aq)
Fe^+2 -2e +Br^- e+ + Mg^+2 -2e =Fe^+2 -2e +MgBr2(aq) -2e e+
Idk what to from here?
I cancel out everything right?
Also, note that bromide is a spectator ion and can be eliminated.
FeBr(aq) +Mg(s) = Fe(s) + MgBr2(aq)
Fe^+2 -2e +Br^- e+ + Mg^+2 -2e =Fe^+2 -2e +MgBr2(aq) -2e e+
Idk what to from here?
I cancel out everything right?
Answers
Answered by
DrBob222
You want to write half reactions but I think you made a typo with FeBr. Should it have been FeBr2
Fe^2+ 2e --> Fe
Mg --> Mg^2+ + 2e
-------------------
Then add the equations.
Fe^2+ 2e --> Fe
Mg --> Mg^2+ + 2e
-------------------
Then add the equations.
Answered by
Feather
Use half-cells to balance the following redox reaction, and label the oxidation and reduction half-reactions.
Also, note that bromide is a spectator ion and can be eliminated.
FeBr3(aq) + Mg(s) à Fe(s) + MgBr2(aq)
Also, note that bromide is a spectator ion and can be eliminated.
FeBr3(aq) + Mg(s) à Fe(s) + MgBr2(aq)
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