Asked by Andra
1) Round 578.683 m, 47.3333 kg, and 789.5 cm to four significant figures.
2) Find the weight of a 12.25 kg dog. Round your answer to the correct number of significant figures. Use weight=massxfree-fall acceleration.
3) Round 3155.24m, 8.777 73 cm, and 93.775 57 kg to one less significant figure than they each have currrently.
4) Multiply 4.135 x 4.688 888 887 m x 8.7m round your answer to the correct number of significant figures.
PLEASE explain each of the answers to me in simple language. I need to submit these by tonight and I struggled and I know my answers are wrong. Thank you.
2) Find the weight of a 12.25 kg dog. Round your answer to the correct number of significant figures. Use weight=massxfree-fall acceleration.
3) Round 3155.24m, 8.777 73 cm, and 93.775 57 kg to one less significant figure than they each have currrently.
4) Multiply 4.135 x 4.688 888 887 m x 8.7m round your answer to the correct number of significant figures.
PLEASE explain each of the answers to me in simple language. I need to submit these by tonight and I struggled and I know my answers are wrong. Thank you.
Answers
Answered by
Damon
1) Round 578.683 m, 47.3333 kg, and 789.5 cm to four significant figures.
0,1,2,3,4 round down
5,6,7,8,9 round up
578.6 83
8 is greater than 4
so this becomes
578.7 meters
47.33 33
3 is less than 4 so this becomes
47.33 kilograms
789.5 cm
This already has four significant figures
0,1,2,3,4 round down
5,6,7,8,9 round up
578.6 83
8 is greater than 4
so this becomes
578.7 meters
47.33 33
3 is less than 4 so this becomes
47.33 kilograms
789.5 cm
This already has four significant figures
Answered by
Damon
2) Find the weight of a 12.25 kg dog. Round your answer to the correct number of significant figures. Use weight=massxfree-fall acceleration.
g is different in different places on earth. We need it to four significant figures because your mass is to four sig figs.
I will call 9.806 65 m/s^2 = 9.807 m/s^2
m g = weight = 12.25 * 9.807 = 120.1 Newtons
g is different in different places on earth. We need it to four significant figures because your mass is to four sig figs.
I will call 9.806 65 m/s^2 = 9.807 m/s^2
m g = weight = 12.25 * 9.807 = 120.1 Newtons
Answered by
Damon
3) Round 3155.24m, 8.777 73 cm, and 93.775 57 kg to one less significant figure than they each have currently.
====================
3155.24
4 is less than 5 so
3155.3
3<5 so
8.7777
93.77557
7>5 so
93.7756
====================
3155.24
4 is less than 5 so
3155.3
3<5 so
8.7777
93.77557
7>5 so
93.7756
Answered by
Damon
4) Multiply 4.135 x 4.688 888 887 m x 8.7m round your answer to the correct number of significant figures.
============================
You only have 2 sig figs because you said
8.7 not 8.70000000
so
19.388555555
is
19 <-------answer
============================
You only have 2 sig figs because you said
8.7 not 8.70000000
so
19.388555555
is
19 <-------answer
Answered by
Andra
Thank you Damon
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