I have news for you; there is no redox here. Prove it?
Let me rewrite it because you've omitted parentheses.
Zn(OH)4^2- ==> ZnO2^2- + 2H2O
Zn(OH)4^2.
Zn = +2
O = 4*-2 = -8
H = 4*+1 = +4
+2-8+4 = -2 which = charge on the complex ion.
ZnO2^2-
Zn = +2
O = 2*-2 = -4
+2-4= -2 and that's the charge on the ion.
You know water is neutral at 2*1 = 2 for H and -2 for O.
There is no LEO or GER
ZnOH4^2- --> ZnO2^2- + 2H2O
What is the oxidation agent, reducing agent, substance oxidized, and substance reduced?
Well, Zn isn't changed either way, so the OH is the only factor left here...
I simplified ZnOH4^-2 --> ZnO2^2- and 2HOH, but still I'm not quite understanding which is which. I know that there is LEO and GER or OIL RIG, but could you clarify this for me?
Thanks.
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