44m/s * 0.7s = 30.8 m. Lead.
d2 = d1 + 14 m.
Vo*t + 0.5a*t^2 = 44t + 14
20t + 3*t^2 = 44t + 14
3t^2 - 24t - 14 = 0
Use Quadratic formula.
t = 8.55 s.
A police car is traveling at a velocity of 20.0 m/s due north, when a car zooms by at a constant velocity of 44.0 m/s due north. After a reaction time 0.700 s the policeman begins to pursue the speeder with an acceleration of 6.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder?
2 answers
Correction:
44m/s * 0.7s = 30.8 m. Lead.
d2 = d1 + 30.8
Vo*t + 0.5a*t^2 = 44t + 30.8
20t + 3t^2 = 44t + 30.8
3t^2 - 24t - 30.8 = 0
Use Quad. Formula.
t = 9.125 s.
44m/s * 0.7s = 30.8 m. Lead.
d2 = d1 + 30.8
Vo*t + 0.5a*t^2 = 44t + 30.8
20t + 3t^2 = 44t + 30.8
3t^2 - 24t - 30.8 = 0
Use Quad. Formula.
t = 9.125 s.