Asked by Jane
A ball falls 5.00 m to the ground. It remains in contact with the ground for 0.027 s and then rebounds to a maximum height of 1.61 m. What acceleration did the ball experience while it was in contact with the ground?
Answers
Answered by
Henry
V^2 = 2g*h = 19.6*5 = 98
V = 9.9 m/s.
V^2 = Vo^2 + 2g*h = 0
Vo^2 - 19.6*1.61 = 0
Vo^2 = 31.556
Vo = 5.62 m/s
a = (5.62-9.9)/0.027 = -158.5 m/s^2.
V = 9.9 m/s.
V^2 = Vo^2 + 2g*h = 0
Vo^2 - 19.6*1.61 = 0
Vo^2 = 31.556
Vo = 5.62 m/s
a = (5.62-9.9)/0.027 = -158.5 m/s^2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.