Question
A ball falls 5.00 m to the ground. It remains in contact with the ground for 0.027 s and then rebounds to a maximum height of 1.61 m. What acceleration did the ball experience while it was in contact with the ground?
Answers
Henry
V^2 = 2g*h = 19.6*5 = 98
V = 9.9 m/s.
V^2 = Vo^2 + 2g*h = 0
Vo^2 - 19.6*1.61 = 0
Vo^2 = 31.556
Vo = 5.62 m/s
a = (5.62-9.9)/0.027 = -158.5 m/s^2.
V = 9.9 m/s.
V^2 = Vo^2 + 2g*h = 0
Vo^2 - 19.6*1.61 = 0
Vo^2 = 31.556
Vo = 5.62 m/s
a = (5.62-9.9)/0.027 = -158.5 m/s^2.