Asked by gisela
Find the sum of the first 60 terms of the arithmetic sequence whose first term is −15 and whose common difference is 7.
Answers
Answered by
Damon
a60 = a1 + (59)(7)
a60 = -15 + 413 = 398
S60 = 60 (-15 + 398) / 2
=11490
a60 = -15 + 413 = 398
S60 = 60 (-15 + 398) / 2
=11490
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