Asked by Alex
I already know the angle of Eastdale which is 45° due to the turn from due east to the northwest. So therefore so I need to find the measures of angle c and angle n. I can use the Law of Sines.
sin‹C/c=sin‹E/e
sin‹C/18=(√2/2)/12.7308
sin‹C=18(√2/2)/12.708=.9998
angle c= 88.8°
So therefore m‹N= 180°-45°-88.8°=46.2°
What did I do wrong?
sin‹C/c=sin‹E/e
sin‹C/18=(√2/2)/12.7308
sin‹C=18(√2/2)/12.708=.9998
angle c= 88.8°
So therefore m‹N= 180°-45°-88.8°=46.2°
What did I do wrong?