Asked by Lissa
My head is spinning from this chapter! I've done most of the questions by myself but I have no idea what formulas I should use for these last two. Can you walk me through them so I can understand what I need to do?
1. What volume of 5.0 M HNO3 is required to neutralize 2500 cm3 of a 2.0 M NaOH solution?
2. Calculate the volume of 0.55M HNO3 necessary to neutralize 5500 cm3 of 0.45M KOH.
1. What volume of 5.0 M HNO3 is required to neutralize 2500 cm3 of a 2.0 M NaOH solution?
2. Calculate the volume of 0.55M HNO3 necessary to neutralize 5500 cm3 of 0.45M KOH.
Answers
Answered by
DrBob222
1. Write and balance the equation.
HNO3 + NaOH ==> NaNO3 + H2O
2. mols NaOH = M x L = 2.0 M x 2.500 L = 5.0
3. Using the coefficients in the balanced equation convert mols NaOH to mols HNO3.
5.0 mols NaOH x (1 mol HNO3/1 mol NaOH) = 5.0 x 1/1 = 5.0 mols HNO3
4. M HNO3 = mols HNO3/L HNO3. You know M and mols, solve for L (convert to mL if needed).
The second problem is the same kind.
HNO3 + NaOH ==> NaNO3 + H2O
2. mols NaOH = M x L = 2.0 M x 2.500 L = 5.0
3. Using the coefficients in the balanced equation convert mols NaOH to mols HNO3.
5.0 mols NaOH x (1 mol HNO3/1 mol NaOH) = 5.0 x 1/1 = 5.0 mols HNO3
4. M HNO3 = mols HNO3/L HNO3. You know M and mols, solve for L (convert to mL if needed).
The second problem is the same kind.
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