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The first step of the synthesis is described by the reaction below. When 1.200 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of...Asked by here
The first step of the synthesis is described by the reaction below. When 2.000 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4, the theoretical yield of FeC2O42H2O is
grams.
Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)
grams.
Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)
Answers
Answered by
DrBob222
Did you omit the arrow? I assume the first line holds the reactants and the second line holds the products.
Convert 2.000 g of the iron ammonium sulfate hexahydrate to mols. Convert 13 mL of the 1 M oxalic acid to mols. Determine the mols of the product formed FROM EACH of the reactants, TAKE THE SMALLER ONE and that will be the limiting reagent. Usual stoichiometry after that. Post your work if you need further assistance.
Convert 2.000 g of the iron ammonium sulfate hexahydrate to mols. Convert 13 mL of the 1 M oxalic acid to mols. Determine the mols of the product formed FROM EACH of the reactants, TAKE THE SMALLER ONE and that will be the limiting reagent. Usual stoichiometry after that. Post your work if you need further assistance.
Answered by
Tokey
the answer is .918
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