Asked by Alvyn

a vessel connected to an open-end mercury manometer is filled with gas to a pressure of .835 atm.the atmospheric pressure is 755 torr.In which arm of the manometer will the level of mercury be higher?What is the height difference between the two arms of manometer?
Answered by DrBob222
See if this helps,
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Since the pressure in the vessel is 0.835 atm(0.835*760 = about 635 mm) and atmospheric pressure is 755 mm in the problem, then the Hg level in the open end will be lower than the closed end so you want to look at #3 I believe. That is
pgas + pheight Hg = patm.
pgas is 635; patm is 755, Solve for pheight Hg.
Answered by Anonymous
80
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