Question

Rationalize the denominator using the conjugate.

1/1-√7+√5

please show all the steps and explain it

Answer 1

1/(1-√7+√5)
multiply top and bottom by 1-√7-√5

(1-√7-√5)/((1-√7)^2 - 5)
= (1-√7-√5)/(1-2√7+7-5)
= (1-√7-√5)/(3-2√7)
now multiply by 3+2√7
(1-√7-√5)(3+2√7)/(9-28)
(1-√7-√5)(3+2√7)/-19

Now just expand and simply the top to get

(11+3√5+√7+2√35)/19

Not sure I don't prefer the original expression

Answer 2

thankyouuu !!