Asked by jane
A .7567 impure KHP was dissolved in water. 26.7 ml of standardized 0.068 M NaOH was used to achieve a phenolphthalein end point. The stoichiometric ratio between KHP and NaOH is 1:1.
What is the percent by mass of KHP in the sample?
What is the percent by mass of KHP in the sample?
Answers
Answered by
DrBob222
mols NaOH = M x L = estimated 0.0018
Therefore, mols KHP = estimated 0.0018
g KHP = mols KHP x molar mass KHP = ?
% KHP = (mass KHP.mass sampe)*100 = ?
Therefore, mols KHP = estimated 0.0018
g KHP = mols KHP x molar mass KHP = ?
% KHP = (mass KHP.mass sampe)*100 = ?
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