Question

Let P=(1,2,-1),Q=(3,-1,4),and R=(2,6,2)
be three vertices of a parallelogram PQRS.
(a) Find the coordinates of S.
(b) Find the area of PQRS.
measuring from P,
(s-p)+(r-s) = (q-p)+(r-q) = r-p
= (2,6,2)-(1,2,-1) = (1,4,3)

the area is |(s-p)x(q-p)|
= |(0,2,4)x(4,-3,5)|
= |22,16,-8|
= √804

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