Asked by Anonymous
I have to determine if this function is either odd or even or neither.
f(x)=x^3*abs(x^3) + x^3
I do not know how to approach this question as the absolute value is giving me trouble. Please help. Thanks.
f(x)=x^3*abs(x^3) + x^3
I do not know how to approach this question as the absolute value is giving me trouble. Please help. Thanks.
Answers
Answered by
Reiny
A function is even if f(-a) = f(a)
a function is odd if f(-a) = -f(a)
f(a) = a^3(a^3) + a^3 = a^3(a^3 + 1)
f(-a) = -(a^3)(a^3) - a^3
= - (a^3)(a^3 + 1)
notice that abs(a^3) is always positive
So what do you think?
You might try it with numbers, e.g.
f(2) = 8(8) + 8 = 72
f(-2) = -8(8) - 8 = -72 = - f(2)
a function is odd if f(-a) = -f(a)
f(a) = a^3(a^3) + a^3 = a^3(a^3 + 1)
f(-a) = -(a^3)(a^3) - a^3
= - (a^3)(a^3 + 1)
notice that abs(a^3) is always positive
So what do you think?
You might try it with numbers, e.g.
f(2) = 8(8) + 8 = 72
f(-2) = -8(8) - 8 = -72 = - f(2)
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