Asked by shakinah
The least common multiple of two numbers is 60 and one of the numbers is 7 less than the other number. What are the numbers? Justify your answer.����
Answers
Answered by
Steve
If the numbers are relatively prime, then
x(x-7) = 60
x^2 - 7x - 60 = 0
(x-12)(x+5) = 0
So, the numbers are 12 and 5
x(x-7) = 60
x^2 - 7x - 60 = 0
(x-12)(x+5) = 0
So, the numbers are 12 and 5
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