Asked by PLEASEEEE HELP
1 mole of nitroglycerin decomposes and release 5.72*10^3 KJ heat. to give CO2 H2O O2 and N2.
A) write the balanced chemical equation
B) calculate the work done assuming the temp of the reaction is 450K
A) write the balanced chemical equation
B) calculate the work done assuming the temp of the reaction is 450K
Answers
Answered by
DrBob222
4 C3H5(NO3)3(s) --> 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g)
Look up the density of nitroglycerin and calculate the volume of 1 mole. Then count the volume produced by the products. That will be 29 mols O2. Use PV = nRT to convert 29 mols at 450K to volume in L. Then delta V is volume products minus volume reactant.
Work done is -p*(delta V). p is 1 atm.
That will give you the work in L*atm and you can convert to J by multiplying by 101.325.
Look up the density of nitroglycerin and calculate the volume of 1 mole. Then count the volume produced by the products. That will be 29 mols O2. Use PV = nRT to convert 29 mols at 450K to volume in L. Then delta V is volume products minus volume reactant.
Work done is -p*(delta V). p is 1 atm.
That will give you the work in L*atm and you can convert to J by multiplying by 101.325.
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