4 C3H5(NO3)3(s) --> 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g)
Look up the density of nitroglycerin and calculate the volume of 1 mole. Then count the volume produced by the products. That will be 29 mols O2. Use PV = nRT to convert 29 mols at 450K to volume in L. Then delta V is volume products minus volume reactant.
Work done is -p*(delta V). p is 1 atm.
That will give you the work in L*atm and you can convert to J by multiplying by 101.325.
1 mole of nitroglycerin decomposes and release 5.72*10^3 KJ heat. to give CO2 H2O O2 and N2.
A) write the balanced chemical equation
B) calculate the work done assuming the temp of the reaction is 450K
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