Asked by johnny

The mean (μ) of the scale is 55 and the standard deviation (σ) is 7. Assuming that the scores are normally distributed, what PERCENTAGE of the population scores are above 59?

Answers

Answered by PsyDAG
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Multiply by 100.
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