Asked by Cynthia
x-8/x-9-x+1/x+9+x-17/x^2-81 =x^3-81x^2-7x-27/x^2.
Can some check this my answer and see if it corre4ct please.
Can some check this my answer and see if it corre4ct please.
Answers
Answered by
Reiny
you appear to have completely ignored the order of operation, you must use brackets to show the expression in its proper way.
I will assume you meant
(x-8)/(x-9) - (x+1)/(x+9) + (x-17)/(x^2-81)
did you notice that x^2-81 = (x+9)(x-9), so x^2-81 is the LCD
then
(x-8)/(x-9) - (x+1)/(x+9) + (x-17)/(x^2-81)
=[(x-8)(x+9) - (x+1)(x-9) + x-17]/(x^2-81)
= [x^2+x-72 - (x^2-8x-9) + x-17]/(x^2-81)
= [x^2+x-72-x^2+8x-9+x-17]/(x^2-81)
= (10x-80)/(x^2-81)
check my steps, I tend to make stupid mistakes when typing and working out these questions at the same time
I will assume you meant
(x-8)/(x-9) - (x+1)/(x+9) + (x-17)/(x^2-81)
did you notice that x^2-81 = (x+9)(x-9), so x^2-81 is the LCD
then
(x-8)/(x-9) - (x+1)/(x+9) + (x-17)/(x^2-81)
=[(x-8)(x+9) - (x+1)(x-9) + x-17]/(x^2-81)
= [x^2+x-72 - (x^2-8x-9) + x-17]/(x^2-81)
= [x^2+x-72-x^2+8x-9+x-17]/(x^2-81)
= (10x-80)/(x^2-81)
check my steps, I tend to make stupid mistakes when typing and working out these questions at the same time
Answered by
Cynthia
Thanks Reiny this is my first time and the operations was not in brackets so I DID NOT KNOW
Answered by
Reiny
No problem,
may people have difficulty writing fractions in this format, it is hard to create them
if you write x-8/x+9
it really means x - 8/x + 9 according to BEDMAS
so it is necessary to use brackets.
may people have difficulty writing fractions in this format, it is hard to create them
if you write x-8/x+9
it really means x - 8/x + 9 according to BEDMAS
so it is necessary to use brackets.
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