Asked by Raven
One base of trapezoid AGIE is four less than three times the other shorter base. The height of the trapezoid is one half of the shorter base. The area of the trapezoid is 210 square inches. Find the lengths of the bases and the height.
Answers
Answered by
Damon
average base = (3b-4+b)/2 = 2b-2
(2b-2)(b/2) = 210
b^2-b-210 = 0
(b-15)(b+14) = 0
b = 15
3b-4 =
b/2 =
(2b-2)(b/2) = 210
b^2-b-210 = 0
(b-15)(b+14) = 0
b = 15
3b-4 =
b/2 =
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