does anyone have a clue how to do this. I am so lost. If you can please explan why you do what you do when working this out so maybe i can better understand this. thanks a bunch.

Question

Prove (algebraically, not numerically) that the product of the solutions of
ax^2+bx+c=0 is c/a

Answer 1

Remember that the quadratic formula gives you the solution
x = (-b ±√(b^2-4ac))/(2a)

so when we multiply these two solutions we get
(-b+√(b^2-4ac))/(2a) * (-b-√(b^2-4ac))/(2a)
= (b^2 - (b^2-4ac))/(4a^2)
= 4ac/(4a^2)
= c/a