Asked by Raven
When nine is added to both the numerator and the denominator of an original fraction, the new fraction equals six sevenths. When seven is subtracted from both the numerator and the denominator of the original fraction, a third fraction is two thirds. Find the original fraction.
Use algebraic equations to justify your answer.
Use algebraic equations to justify your answer.
Answers
Answered by
Steve
Just put the words into symbols. If the original fraction is n/d, then
(n+9)/(d+9) = 6/7
(n-7)/(d-7) = 2/3
Now just solve for n and d.
(n+9)/(d+9) = 6/7
(n-7)/(d-7) = 2/3
Now just solve for n and d.
Answered by
Raven
I'm not really sure how I'm supposed to solve for n or d.
Answered by
Steve
as usual, first just clear fractions:
(n+9)(7) = 6(d+9)
(n-7)(3) = 2(d-7)
7n+63 = 6d+54
3n-21 = 2d-14
7n-6d = -9
3n-2d = 7
Now can you solve for n and d?
(n+9)(7) = 6(d+9)
(n-7)(3) = 2(d-7)
7n+63 = 6d+54
3n-21 = 2d-14
7n-6d = -9
3n-2d = 7
Now can you solve for n and d?
Answered by
Anonymous
15/19
Answered by
Anonymous
isnt it 1/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.