Asked by David
                Let x and y be real numbers such that x^2 + y^2 = 1. Find the maximum value of 2x - 5y. 
            
            
        Answers
                    Answered by
            Damon
            
    y = +/- sqrt(1-x^2)
if y is to be real, x must be
x^2 </= 1
-1 < x < +1
similarly y ranges from -1 to + 1
so our function 2 x - 5y
is maximum when x is 1 and y is -1
2 + 5 = 7
    
if y is to be real, x must be
x^2 </= 1
-1 < x < +1
similarly y ranges from -1 to + 1
so our function 2 x - 5y
is maximum when x is 1 and y is -1
2 + 5 = 7
                    Answered by
            Steve
            
    but, at (1,-1), x^2+y^2 = 2
The maximum occurs when
x = 2/√29
y = -5/√29
    
The maximum occurs when
x = 2/√29
y = -5/√29
                    Answered by
            Anonymous
            
    Let x and y be real numbers such that x^2 + y^2 = 1. What is the maximum value of 2x - 5y?
    
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