Asked by Anonymous

25.0 mL of ethanol (density = 0.789 g/mL) initially at 5.5°C is mixed with 32.3 mL of water (density = 1.0 g/mL) initially at 25.3°C in an insulated beaker. Assuming that no heat is lost, what is the final temperature of the mixture?

Answers

Answered by DrBob222
You will need to look up the specific heat of H2O and the specific heat of ethanol.
heat lost by H2O + heat gained by ethanol = 0
First, use density to convert volumes to grams of each. mass = volume x density
[mass H2O x specific heat H2O x (Tfinal-Tinitial)] + [mass ethanol x specific heat ethanol x (Tfinal-Tinitial)]=0
Substitute and solve for Tfinal.
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