11. The second of two numbers is 5 more than twice the first. The sum of the numbers is 44. Find the numbers by writing and solving a system of equations.

Answer 1

Let's call the first number "x" and the second number "y".

From the first sentence, we know that:

y = 2x + 5

From the second sentence, we know that:

x + y = 44

Now we have two equations with two variables, which we can solve for x and y.

We can start by substituting the first equation into the second equation:

x + (2x + 5) = 44

Simplifying, we get:

3x + 5 = 44

Subtracting 5 from both sides:

3x = 39

Dividing both sides by 3:

x = 13

Now that we know x is 13, we can use the first equation to find y:

y = 2x + 5

y = 2(13) + 5

y = 31

So the two numbers are 13 and 31.